-6w^2+150=0

Solution for -6w^2+150=0 equation:

-6w^2+150=0

a = -6; b = 0; c = +150;
Δ = b2-4ac
Δ = 02-4·(-6)·150
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-6}=\frac{-60}{-12}
=+5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-6}=\frac{60}{-12}
=-5
$